Low Pass Filter
#) Which allow to pass low frequency components and attenuates high
frequency components
#) The capacitive reactance Xc=1/(Cx2(pi)f).
#) That is capacitive reactance decreases with increase in frequency
#) Now at the high frequency, the capacitor act as a vertual short circuit which
directs the input signal to ground thus the output falls to zero
#) At low frequency, Capacitor acts as open circuit, and the entire signal
appear at the output
#) By observing above wave form we can see that the Amplitude decreases
when frequency increases
Integrator
#) Same circuit can be used as an Integrator
#) An Integrator does the mathematical operation 'Integration' on the input
signal
#) The time constant RC is very high as compared to time period of input
signal
#) When pulse waveform is applied to the circuit, capacitor charges through
the resistor abd hence the output voltage buildup
#) When the input is terminated capacitor starts to discharge.
#) Thus we get a Triangular waveform
#) As the value of RC increases amplitude of the output decreases (See above
fig) because it take more time to charge and discharge
How do I learn more about a certain type of wave which may best be described as being that of pulses of capacitive reactance?…
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